## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 16 - Problems - Page 618: 89

#### Answer

The magnitude of the electric force exerted on the raindrop is $2.56\times 10^{-12}~N$ and this force is directed downward.

#### Work Step by Step

We can find the magnitude of the electric force on the raindrop: $F = E~\vert q \vert$ $F = (2.0\times 10^6~N/C)(8)(1.6\times 10^{-19}~C)$ $F = 2.56\times 10^{-12}~N$ Since the charge on the raindrop is negative, the force exerted on the raindrop is directed downward. The magnitude of the electric force exerted on the raindrop is $2.56\times 10^{-12}~N$ and this force is directed downward.

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