#### Answer

An object with a mass of $5.9~kg$ that is near the Earth's surface would have this magnitude of gravitational force exerted on it.

#### Work Step by Step

We can find the electric force:
$F = \frac{k~q_p~q_p}{r^2}$
$F = \frac{(9.0\times 10^9~N~m^2/C^2)~(1.6\times 10^{-19}~C)(1.6\times 10^{-19}~C)}{(2.0\times 10^{-15}~m)^2}$
$F = 57.6~N$
We can find the mass of an object near the Earth's surface with this magnitude of gravitational force:
$F = ma$
$m = \frac{F}{a}$
$m = \frac{57.6~N}{9.80~m/s^2}$
$m = 5.9~kg$
An object with a mass of $5.9~kg$ that is near the Earth's surface would have this magnitude of gravitational force exerted on it.