College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 14 - Problems - Page 535: 46


The rate of heat loss due to panting is $252~W$

Work Step by Step

We can find the mass of water that evaporates in one minute: $m = (0.010~g)(670) = 6.7~g$ We can find the heat required to evaporate 6.7 grams of water: $Q = m~V$ $Q = (6.7~g)(2260~J/g)$ $Q = 15,142~J$ We can find the rate of heat lost through panting: $P = \frac{Q}{t} = \frac{15,142~J}{60~s} = 252~W$ The rate of heat loss due to panting is $252~W$
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