## College Physics (4th Edition)

It is possible for the aluminum to melt an equal mass of ice. The initial temperature of the aluminum is $370^{\circ}C$
The heat required to melt the ice is equal in magnitude to the loss of heat from the aluminum as it cools. We can find the required temperature of the aluminum to melt an equal mass of ice: $m_a~c_a~\Delta T = m_i~L$ $c_a~\Delta T = L$ $\Delta T = \frac{L}{c_a}$ $\Delta T = \frac{333\times 10^3~J/kg}{900~J/kg~C^{\circ}}$ $\Delta T = 370~C^{\circ}$ It is possible for the aluminum to melt an equal mass of ice. The initial temperature of the aluminum is $370^{\circ}C$, which is well below the melting point of aluminum $(660^{\circ}C)$.