## College Physics (4th Edition)

The fundamental frequency would be $396~Hz$
(a) At a temperature of $0.0^{\circ}C$, the speed of sound in air is $331~m/s$. We can find the length of the pipe: $\lambda = \frac{v}{f}$ $2L = \frac{v}{f}$ $L = \frac{v}{2f}$ $L = \frac{331~m/s}{(2)(382~Hz)}$ $L = 0.433~m$ At a temperature of $20.0^{\circ}C$, the speed of sound in air is $343~m/s$. We can find the fundamental frequency: $f = \frac{v}{\lambda}$ $f = \frac{v}{2L}$ $f = \frac{343~m/s}{(2)(0.433~m)}$ $f = 396~Hz$ The fundamental frequency would be $396~Hz$.