## College Physics (4th Edition)

(a) The length of the pipe should be $0.328~m$ (b) The fundamental frequency is $252.3~Hz$
(a) We can find the length of the pipe: $\lambda = \frac{v}{f}$ $4L = \frac{v}{f}$ $L = \frac{v}{4f}$ $L = \frac{343~m/s}{(4)(261.5~Hz)}$ $L = 0.328~m$ The length of the pipe should be $0.328~m$ (b) At a temperature of $0.0^{\circ}C$, the speed of sound in air is $331~m/s$. We can find the fundamental frequency: $f = \frac{v}{\lambda}$ $f = \frac{v}{4L}$ $f = \frac{331~m/s}{(4)(0.328~m)}$ $f = 252.3~Hz$ The fundamental frequency is $252.3~Hz$