College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 10 - Problems - Page 401: 71


The length of the pendulum is $0.25~m$

Work Step by Step

We can find the length of the pendulum: $T = 2\pi~\sqrt{\frac{L}{g}}$ $(\frac{T}{2\pi})^2 = \frac{L}{g}$ $L = \frac{T^2~g}{(2\pi)^2}$ $L = \frac{(1.0~s)^2~(9.80~m/s^2)}{(2\pi)^2}$ $L = 0.25~m$ The length of the pendulum is $0.25~m$.
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