College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 10 - Problems - Page 401: 67

Answer

The period of this pendulum is still $1.5~s$

Work Step by Step

We can write an expression for the original period of the pendulum: $T = 2\pi~\sqrt{\frac{L}{g}}$ The period does not depend on the mass or the amplitude, so changing the mass and the amplitude does not affect the period. The period of this pendulum is still $1.5~s$
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