## College Physics (4th Edition)

The frequency of the oscillations is $0.25~s$
In general: $y(t) = A~sin(\omega~t+\phi)$ In this case: $y(t) = (8.0~cm)~sin~[~(1.57~rad/s)~t~]$ We can see that $\omega = 1.57~rad/s$. We can find the frequency of the oscillations: $f = \frac{\omega}{2\pi}$ $f = \frac{1.57~rad/s}{2\pi}$ $f = 0.25~s$ The frequency of the oscillations is $0.25~s$.