College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 10 - Problems - Page 400: 57


The frequency of the oscillations is $0.25~s$

Work Step by Step

In general: $y(t) = A~sin(\omega~t+\phi)$ In this case: $y(t) = (8.0~cm)~sin~[~(1.57~rad/s)~t~]$ We can see that $\omega = 1.57~rad/s$. We can find the frequency of the oscillations: $f = \frac{\omega}{2\pi}$ $f = \frac{1.57~rad/s}{2\pi}$ $f = 0.25~s$ The frequency of the oscillations is $0.25~s$.
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