College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 10 - Problems - Page 400: 55


The period of oscillation is $0.70~s$

Work Step by Step

We can find the value of $k$ for this system: $kd = mg$ $k = \frac{mg}{d}$ $k = \frac{(92~kg)(9.80~m/s^2)}{0.080~m}$ $k = 11,270~N/m$ We can find the period of oscillation: $T = \frac{2\pi}{\omega}$ $T = 2\pi~\sqrt{\frac{m}{k}}$ $T = 2\pi~\sqrt{\frac{47~kg+92~kg}{11,270~N/m}}$ $T = 0.70~s$ The period of oscillation is $0.70~s$
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