## College Physics (4th Edition)

The period of oscillation is $0.70~s$
We can find the value of $k$ for this system: $kd = mg$ $k = \frac{mg}{d}$ $k = \frac{(92~kg)(9.80~m/s^2)}{0.080~m}$ $k = 11,270~N/m$ We can find the period of oscillation: $T = \frac{2\pi}{\omega}$ $T = 2\pi~\sqrt{\frac{m}{k}}$ $T = 2\pi~\sqrt{\frac{47~kg+92~kg}{11,270~N/m}}$ $T = 0.70~s$ The period of oscillation is $0.70~s$