## College Physics (4th Edition)

The volume of the sphere decreases by a fraction of $7.69\times 10^{-4}$ The radius decreases by a fraction of $2.56\times 10^{-4}$
We can find the fraction that the volume changes: $\frac{\Delta V}{V_0} = -\frac{1}{B}~\Delta P$ $\frac{\Delta V}{V_0} = -\frac{1}{130\times 10^9~Pa}~(100\times 10^6~Pa)$ $\frac{\Delta V}{V_0} = -7.69\times 10^{-4}$ The volume of the sphere decreases by a fraction of $7.69\times 10^{-4}$ We can find the fraction that the radius changes: $\frac{\Delta r}{r_0} \approx \frac{-7.69\times 10^{-4}}{3} = -2.56\times 10^{-3}$ The radius decreases by a fraction of $2.56\times 10^{-4}$