## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 10 - Problems - Page 398: 17

#### Answer

The effective cross-sectional area of a human femur is $3.125~cm^2$ The effective cross-sectional area of a horse femur is $7.14~cm^2$

#### Work Step by Step

We can find the effective cross-sectional area of a human femur: $\frac{F}{A} = 1.6\times 10^8~Pa$ $A = \frac{F}{1.6\times 10^8~Pa}$ $A = \frac{5\times 10^4~N}{1.6\times 10^8~Pa}$ $A = 3.125\times 10^{-4}~m^2$ $A = 3.125~cm^2$ The effective cross-sectional area of a human femur is $3.125~cm^2$ We can find the effective cross-sectional area of a horse femur: $\frac{F}{A} = 1.4\times 10^8~Pa$ $A = \frac{F}{1.4\times 10^8~Pa}$ $A = \frac{10\times 10^4~N}{1.4\times 10^8~Pa}$ $A = 7.14\times 10^{-4}~m^2$ $A = 7.14~cm^2$ The effective cross-sectional area of a horse femur is $7.14~cm^2$.

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