Answer
$q=\frac{1}{2}$ and $ p=\frac{1}{2}$
and $v=K\sqrt ((lambda) \times g)$
Work Step by Step
$\frac{m}{s}=m^{p}.\frac{m^{q}}{s^{2q}}=\frac{m^{p+q}}{s^{2q}}$
From above, we have
$2q=1$ and $p+q=1$
Thus, $q=\frac{1}{2}$ and $ p=\frac{1}{2}$
and $v=K\sqrt ((lambda) \times g)$
