College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Problems - Page 23: 88


$q=\frac{1}{2}$ and $ p=\frac{1}{2}$ and $v=K\sqrt ((lambda) \times g)$

Work Step by Step

$\frac{m}{s}=m^{p}.\frac{m^{q}}{s^{2q}}=\frac{m^{p+q}}{s^{2q}}$ From above, we have $2q=1$ and $p+q=1$ Thus, $q=\frac{1}{2}$ and $ p=\frac{1}{2}$ and $v=K\sqrt ((lambda) \times g)$
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