College Physics (4th Edition)

$q=\frac{1}{2}$ and $p=\frac{1}{2}$ and $v=K\sqrt ((lambda) \times g)$
$\frac{m}{s}=m^{p}.\frac{m^{q}}{s^{2q}}=\frac{m^{p+q}}{s^{2q}}$ From above, we have $2q=1$ and $p+q=1$ Thus, $q=\frac{1}{2}$ and $p=\frac{1}{2}$ and $v=K\sqrt ((lambda) \times g)$