College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Problems - Page 23: 93

Answer

$0.46s^{-1}$

Work Step by Step

The square root of k/m has dimensions of inverse time, which is correct for frequency, $f_{1}=\sqrt \frac{k}{m_{1}}$ or, $k=m_{1}f_{1}^{2}$ Thus frequency of chair with 75-kg astronaut is $f_{2}=f_{1}\sqrt \frac{m_{1}}{m_{2}}=(0.5)\sqrt (\frac{62+10}{75+10})=0.46s^{-1}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.