Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 9 - Section 9.1 - Center of Mass - Example - Page 155: 9.4

Answer

$-4.6m$

Work Step by Step

The initial and final centers of mass must be equal. Thus, it follows: $\frac{m_Jx_{Ji}}{M}= \frac{m_J \times(x_{Ji} + 19 + x_{cf})+m_cx_{cf}}{M}$ We simplify to find: $x_{cf} = \frac{-19m_J}{m_J+m_c}$ Plugging in 4.8 for $m_J$ and 15 for $m_c$, it follows: $x_{cf}=-4.6\ m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.