Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 8 - Exercises and Problems - Page 149: 78

Answer

b) $5.5 \ km/s$

Work Step by Step

We use the equation for escape speed to find: $V_{esc} =\sqrt{\frac{2GM}{r}}$ $V_{esc} =\sqrt{\frac{2(6.67\times10^{-11})(5.97\times10^{24})}{6.37\times10^6+(20.2\times10^6)}}=5470\ m/s = 5.5 \ km/s$
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