Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 8 - Exercises and Problems - Page 149: 79

Answer

Please see the work below.

Work Step by Step

We know that $E=-\frac{GMm}{2r}$ We plug in the known values to obtain: $E=-\frac{6.67\times 10^{-11}(5.97\times 10^{24})(844)}{(2)(20.2\times 10^6+6.37\times 10^6)}=-6GJ$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.