Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 7 - Exercises and Problems - Page 132: 55


Please see the work below.

Work Step by Step

We know that according to law of conservation of energy $(\frac{1}{2})kx^2=\mu m\space g\space d$ This simplifies to: $d=\frac{kx^2}{2\mu\space m\space g}$ We plug in the known values to obtain: $d=\frac{(340)(0.18)^2}{(2)(0.27)(1.5)(9.8)}=1.4m$
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