Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 6 - Section 6.2 - Work - Example - Page 99: 6.3

Answer

a) 1510 MJ b) $12^{\circ}$

Work Step by Step

We use the equation for work: $W = F_x\Delta x + F_y\Delta y$ $W = (1.2)(380) + (2.3)(460) = 1510 \ MJ$ We use the Pythagorean theorem to find: $ F = \sqrt{ 1.2^2 + 2.3^2} = 2.59 \ MN$ Thus: $\theta = cos^{-1} (\frac{1510}{2.59 \times 597}) \approx 12^{\circ}$
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