Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 6 - Section 6.2 - Work - Example - Page 98: 6.2

Answer

$2.2 \ kJ$

Work Step by Step

We find: $ W = F_x \Delta x \\ W = 60cos35^{\circ}\times 45 = 2.2 \ kJ$
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