Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 6 - Exercises and Problems - Page 110: 57

Answer

$W = x-\frac{x^2}{2L_0}+\frac{L_0^2}{L_0+x}-L_0$

Work Step by Step

We know the following equation for work: $W=\int_0^{x}F(x)dx$ Thus, we find: $W=\int_0^{x}F_0[\frac{L_0-x}{L_0}-\frac{L_0^2}{(L_0+x)^2}]dx$ $W=\int_0^{x}F_0[1-\frac{x}{L_0}-\frac{L_0^2}{(L_0+x)^2}]dx$ $W = x-\frac{x^2}{2L_0}+\frac{L_0^2}{L_0+x}-L_0$
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