Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 6 - Exercises and Problems - Page 110: 45

Answer

$856.5\space W$

Work Step by Step

Here we use the equation $P=FV$, where P - Power, F- Force applied, and V- Speed of the bicycle. First of all, we have to convert $18.5\space km/h$ into m/s by multiplying this value by 1000m/ km, 1h/3600 s conversion factors. $18.5\space km/h= (\frac{18.5\space km}{h})(\frac{1000m}{km})(\frac{1h}{3600\space s})= 5.1\space m/s$ Let's apply equation $F=ma$ to the bicycle to find the applied force for the bicycle by us. $\nearrow \angle 6.22^{\circ} F=ma$ ; Let's plug known values into this equation $F-10.8N-148gsin6.22^{\circ}\space N=0$ $F=(10.8+148\times 9.8\times 0.1)N$ $F=167.9\space N$ Let's write, $P=FV$ ; Let's plug known values into this equation $P= 167.9\space N\times5.1\space m/s$ $P=856.5\space W$
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