Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 3 - Exercises and Problems - Page 50: 26

Answer

$261 \ m/s$

Work Step by Step

We create a right triangle, with one side being the plane's velocity and actual velocity and the other side being the plane's speed. Thus, we find the plane's actual velocity first: $\frac{1500}{1.67}=900 \ km/h$ We now find the components of the plane's $1000 \ km/h$ velocity: $v_x=1000cos(15^{\circ})=965.93 \ km/h $ $v_y = 1000sin(15^{\circ})=258.81 \ km/h$ Thus, we find the wind's speed: $v=\sqrt{(258.81)^2+(1000-965.93)^2}=261 \ m/s$
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