## Essential University Physics: Volume 1 (4th Edition)

$\vec{d} = 2.9\hat{i}+4.5\hat{j}$ $\vec{v} = 8.3\hat{i}+12.9\hat{j}$
We first add the displacement vectors to have: $\vec{d}=\vec{d_1}+\vec{d_2}+\vec{d_3}$ $\vec{d}=(40mi/h)(1/6 h)\hat{i} + (5 mi) \hat{j} + (-cos(45)*30*.1)\hat{i} \ mi-(sin(45)*30*.1)\hat{j} \ mi)$ This gives: $\vec{d} = 2.9\hat{i}+4.5\hat{j}$ We know that $\vec{v}$ is found by dividing the overall displacement by the total time, which is .35 h. We divide to find: $\vec{v} = 8.3\hat{i}+12.9\hat{j}$