Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 3 - Exercises and Problems - Page 50: 20


$\vec{d} = 2.9\hat{i}+4.5\hat{j}$ $\vec{v} = 8.3\hat{i}+12.9\hat{j}$

Work Step by Step

We first add the displacement vectors to have: $\vec{d}=\vec{d_1}+\vec{d_2}+\vec{d_3}$ $\vec{d}=(40mi/h)(1/6 h)\hat{i} + (5 mi) \hat{j} + (-cos(45)*30*.1)\hat{i} \ mi-(sin(45)*30*.1)\hat{j} \ mi)$ This gives: $\vec{d} = 2.9\hat{i}+4.5\hat{j}$ We know that $\vec{v}$ is found by dividing the overall displacement by the total time, which is .35 h. We divide to find: $\vec{v} = 8.3\hat{i}+12.9\hat{j}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.