## Essential University Physics: Volume 1 (4th Edition)

$21^{\circ}C$
We use the equation for H to find: $H = (120 \ W/^{\circ}C)(\Delta T)$ $\Delta T = \frac{H}{120 \ W/^{\circ}C}$ $\Delta T = \frac{2.5 \times 10^3 \ W}{120 \ W/^{\circ}C} = 21^{\circ}C$