Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 16 - Section 16.4 - Thermal-Energy Balance - Example - Page 306: 16.7

Answer

$82^{\circ}F$

Work Step by Step

We first must find the value of H for the walls and for the glass: $H_{walls} = \frac{A_{walls}\Delta T}{R_{walls}}= \frac{(300) \Delta T}{30}=10 \Delta T$ $H_{glass} = \frac{A_{glass}\Delta T}{R_{glass}}= \frac{(250) \Delta T}{1.8}=139\Delta T$ We divide the total heat loss by the total heat gain to find: $\Delta T = \frac{1 \times 10^4}{149}=67^{\circ}F$ Thus, when it is 15 degrees outside, it is $82^{\circ}F$ inside.
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