Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 16 - Section 16.4 - Exercises and Problems - Page 309: 16

Answer

Please see the work below.

Work Step by Step

We can find the temperature in Celsius as $T_C=T_K-273.15$ We plug in the known values to obtain: $T_C=77.3-273.15$ $T_C=-196C^{\circ}$ We can find the temperature in Fahrenheit as $T_F=(\frac{9}{5})T_C+32$ We plug in the known values to obtain: $T_F=(\frac{9}{5})(77.3-273.15)+32$ $T_F=-321^{\circ}F$
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