Answer
Please see the work below.
Work Step by Step
We know that
$T_F=(\frac{9}{5})T_C+32$
We plug in the known values to obtain:
$T_F=(\frac{9}{5})(-15)+32$
$T_F=5.0F^{\circ}$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 16 - Section 16.4 - Exercises and Problems - Page 309: 12
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