Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 15 - Section 15.5 - Applications of Fluid Dynamics - Example - Page 283: 15.6

Answer

$v =\sqrt{2gh}$

Work Step by Step

We use known equations, including the Bernoulli equation, to find: $ p_a + \rho gh = p_a + \frac{1}{2}\rho v^2 $ $ \rho gh = \frac{1}{2}\rho v^2 $ $ gh = \frac{1}{2} v^2 $ $v =\sqrt{2gh}$
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