Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 15 - Section 15.4 - Fluid Dynamics - Example - Page 282: 15.5

Answer

18 meters

Work Step by Step

We solve for the depth to obtain: $d_2 = \frac{v_1w_1d_1}{v_2w_2} = \frac{(2.2)(4.5)(40)}{(6)(3.7)}=18 \ m$
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