## Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson

# Chapter 15 - Exercises and Problems - Page 289: 18

6.3 kilometers

#### Work Step by Step

We first need to find the difference in pressure between the inside and the outside of the cabin: $p = 62 \times 10^6 kPa - 1.01 \times 10^5 Pa = 6.19 \times 10^7 Pa$ We now can find how far it can go down: $h = \frac{P - P_{atm}}{\rho g}= \frac{ 6.19 \times 10^7 - 1.01 \times 10^5}{1000 \times 9.81} = 6300 m = 6.3 km$

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