## Essential University Physics: Volume 1 (4th Edition) Clone

We know that the area is $A=\pi r^2$ $A=(3.1416)(\frac{0.0015}{2})^2=7.67\times 10^{-6}m^2$ The pressure is $P=120atm=(120)(1.01\times 10^5)Pa=1.212\times 10^7Pa$ Now we can find the force as $F=PA$ $F=(1.212\times 10^7)(1.767\times 10^{-6})$ $F=21N$