Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 13 - Exercises and Problems - Page 247: 61

Answer

$U =\frac{1}{2}mgL\theta^2 $

Work Step by Step

We use integration to find: $ U = \int Fdx \\ U = \int_0^{\theta} mgsin\theta L d\theta $ $U = \int_0^{\theta} mg L \theta d\theta \\ U =\frac{1}{2}mgL\theta^2 $
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