Answer
a) 1.3 N/m
b) .8 kilograms
Work Step by Step
b) From the original equation, we find:
$m = \frac{4}{5}=.8 \ kg$
a) We know:
$T^2 = 4\pi^2 \frac{k}{m}$
$4+5m=4\pi^2\frac{k}{m}$
$(4+5(.8))^2=4\pi^2\frac{k}{.8} \\ k = 1.3 \ N/m$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 13 - Exercises and Problems - Page 247: 57
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