Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 13 - Exercises and Problems - Page 247: 57


a) 1.3 N/m b) .8 kilograms

Work Step by Step

b) From the original equation, we find: $m = \frac{4}{5}=.8 \ kg$ a) We know: $T^2 = 4\pi^2 \frac{k}{m}$ $4+5m=4\pi^2\frac{k}{m}$ $(4+5(.8))^2=4\pi^2\frac{k}{.8} \\ k = 1.3 \ N/m$
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