Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 11 - Exercises and Problems - Page 209: 58



Work Step by Step

a) We find the final angular velocity: $\omega_f = \frac{(.044)(.035)^2}{(.044)(.035)^2+(.27)(.023)^2}\times180 = 140\ rpm$ b) We find: $percent \ lost = 100\times\frac{k_i-k_f}{k_i}$ Use the fact that $k=\frac{1}{2}I\omega^2$, it follows: $percent \ lost \approx \fbox{25%}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.