## Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson

# Chapter 11 - Exercises and Problems - Page 209: 57

#### Answer

a) 1.61 b) The day increases by a factor of 2.221.

#### Work Step by Step

a) We find: $\frac{R}{R_0}=(\sqrt[3] {\frac{1}{1-.8^3}})^2 = 1.61$ b) Using the equation for the volume of a sphere and the equation for moment of inertia, we find that $r^2\times r^3 =r^5$. Consequently, we can find the ratios of periods to be: $=(1.27)^5\times(1-.8^5)=2.221$ The day increases by a factor of 2.221.

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