Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 1 - Exercises and Problems - Page 13: 55

Answer

a) $1.6 \times 10^{-9} m$ b) $s = 5 \times 10^5$

Work Step by Step

The size is given by: $S = A/N$ Where A is the area and N is the number of chips. $S = \frac{(4 mm)^2}{10^{10}}$ $1.6 \times 10^{-9} mm^2$ b) We now find: $t = \frac{Nd}{v}$ The speed is 2/3 the speed of light, so the number of calculations per second, s, is: $s = 1/t = (\frac{10^{10}4*10^{-8}}{2/3*3*10^8})^{-1}$ $s = 5 \times 10^5$
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