Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 1 - Exercises and Problems - Page 13: 40

Answer

$30\space degrees\space per\space hour$

Work Step by Step

To find the solution, we need to convert 2 rev/ day into degrees/h. $1\space rev= 360\space degrees,$ so we can multiply revolutions by the ratio $360\space degrees/rev$ to get degrees. Similarly $1\space day = 24\space h$. We can use the conversion factor of $24\space h/day$ to convert days into hours. Combining these two conversions gives, $2\space rev /day = (\frac{2\space rev}{day})\times(\frac{360\space degrees}{ rev})\times(\frac{1\space day}{24\space hour})$ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space= \frac{720}{24}\space rev/day$ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space = 30\space degrees/h $ $$Answer\space is\space 30\space degrees\space per\space hour$$
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