Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 1 - Exercises and Problems - Page 13: 50

Answer

$2.28\times10^{9}$

Work Step by Step

We can find the average lifespan of a human = 72.35 yrs. We know that, $1\space yr = 365\times24\times60\times60\space s$ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space = 31536\times10^{3} s$ By using the above conversion factor, we can write, Average lifespan of a human $= 72.35\space yr \times 31356\times10^{3}\space \frac{s}{yr}$ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space = 2.28\times10^{9}\space s\space-(1)$ Human heart beat $=1\space s\space -(2)$ $(1)\div(2)=\gt$ Number of heartbeats in typical human lifetime$\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space= \frac{2.28\times10^{9}\space s}{1\space s}$ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space = 2.28\times10^{9}$
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