Answer
** Draw the arrows on the left side of the reaction.
- One arrow going from the Carbon-Bromine bond to the bromine.
(Bond to Lone Pair)
- One arrow going from the Chloride to form a bond between the Cl and the carbon that was making a bond with the Bromine. (Lone Pair to Bond).
Work Step by Step
1. Identify the bonds that are breaking and the atoms that are losing a pair of electrons
- If you have any trouble, draw the missing electrons on the atoms that are changing their charges.
- The bond between the carbon and the bromine is breaking.
- The Cl had 4 lone pairs on the left, and has 3 lone pairs on the right.
- These are the tails of the arrows.
2. Identify the bonds that are being formed and the atoms that are getting a pair of electrons.
- The Chlorum is making a bond with a carbon.
- The bromine had 3 lone pairs on the left, and has 4 lone pairs on the right.
- These are the heads of the arrows.
** For the chlorum you can:
- Put the head of the arrow on the carbon that is making the bond.
or
- Draw a dotted line between the chlorum and the carbon, representing the bond, and put the head of the arrow on it.
3. Complete the chlorum arrow and the bromine arrow.
