Answer
The compound has 4 geometric isomers. The structures are drawn and labeled in the attached image.
Work Step by Step
The compound has 4 geometric isomers:
$(2Z,5E)-3,7-dichloroocta-2,5-diene$
$(2E,5E)-3,7-dichloroocta-2,5-diene$
$(2Z,5Z)-3,7-dichloroocta-2,5-diene$
$(2E,5Z)-3,7-dichloroocta-2,5-diene$
The structures are drawn and labeled in the attached image.