Answer
The IUPAC name of the compound is $(2E,4Z)-5,6-dimethylhepta-2,4-diene.$
Work Step by Step
The compound has 7 carbon atoms in its longest carbon chain containing the double bond ($hept-$). It has 2 $methyl-$ substituent at positions 5 and 6, and 2 double bonds at positions 2 and 4. The bond at position 2 is of $E$ stereo isomerism and the bond at position 4 is of $Z$ stereo isomerism So, the IUPAC name of the alkene is $(2E,4Z)-5,6-dimethylhepta-2,4-diene.$
