## Introductory Chemistry (5th Edition)

1. Write the $K_{sp}$ expression: $PbCl_2(s) \lt -- \gt 1Pb^{2+}(aq) + 2Cl^{-}(aq)$ $1.17 \times 10^{-5} = [Pb^{2+}]^ 1[Cl^{-}]^ 2$ $1.17 \times 10^{-5} = [Pb^{2+}]^1 \times (2.86 \times 10^{-2})^ 2$ $1.17 \times 10^{-5} = [Pb^{2+}] \times 8.18 \times 10^{-4}$ $\frac{1.17 \times 10^{-5}}{8.18 \times 10^{-4}} = [Pb^{2+}]$ $[Pb^{2+}] = 0.0143M$