Answer
The $K_{sp}$ for $AgI$ is equal to $8.5 \times 10^{-17}$
Work Step by Step
1. Write the $K_{sp}$ expression, and calcule its value:
$ AgI(s) \lt -- \gt 1Ag^{+}(aq) + 1I^{-}(aq)$
$K_{sp} = [Ag^{+}]^ 1[I^{-}]^ 1$
$K_{sp} = (9.2 \times 10^{-9}) \times (9.2 \times 10^{-9})$
$K_{sp} = 8.5 \times 10^{-17}$
