#### Answer

12.5 kJ

#### Work Step by Step

The heat of fusion is the change in enthalpy resulting from providing energy, heat, to a specific quantity of the substance to change its state from a solid to a liquid at constant pressure.
Here given heat of fusion of water is 6.02kJ/mol
Molar mass of water= 18g/mol.
the mass of ice to be melted = 37.4 g.
1mol of water contains 18g of water.
So, 37.4 g of water has 2.07 mol of water.
37.4g = 37.4g x (1mol/ 18g)= 2.07 mol
So for 2.07 mol dH fusion = ?
2.07 mol = 2.07 mol x(6.02 kJ/ 1mol)= 12.5 kJ
To melt 37.4 g of water 12.5kJ of heat is required.