Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 12 - Liquids, Solids, and Intermolecular Forces - Exercises - Problems - Page 441: 57


12.5 kJ

Work Step by Step

The heat of fusion is the change in enthalpy resulting from providing energy, heat, to a specific quantity of the substance to change its state from a solid to a liquid at constant pressure. Here given heat of fusion of water is 6.02kJ/mol Molar mass of water= 18g/mol. the mass of ice to be melted = 37.4 g. 1mol of water contains 18g of water. So, 37.4 g of water has 2.07 mol of water. 37.4g = 37.4g x (1mol/ 18g)= 2.07 mol So for 2.07 mol dH fusion = ? 2.07 mol = 2.07 mol x(6.02 kJ/ 1mol)= 12.5 kJ To melt 37.4 g of water 12.5kJ of heat is required.
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