Work Step by Step
The heat of fusion is the change in enthalpy resulting from providing energy, heat, to a specific quantity of the substance to change its state from a solid to a liquid at constant pressure. Here given heat of fusion of water is 6.02kJ/mol Molar mass of water= 18g/mol. the mass of ice to be melted = 37.4 g. 1mol of water contains 18g of water. So, 37.4 g of water has 2.07 mol of water. 37.4g = 37.4g x (1mol/ 18g)= 2.07 mol So for 2.07 mol dH fusion = ? 2.07 mol = 2.07 mol x(6.02 kJ/ 1mol)= 12.5 kJ To melt 37.4 g of water 12.5kJ of heat is required.