Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 11 - Gases - Exercises - Problems - Page 404: 88

Answer

(a) 7.80 g (b) 0.405 g (c) 0.248 g

Work Step by Step

(a) $5.82\,L\,NO\times\frac{1\,mol\,NO}{22.4\,L\,NO}\times\frac{30.01\,g\,NO}{1\,mol\,NO}$ $= 7.80\,g$ (b) $0.324\,L\,N_{2}\times\frac{1\,mol\,N_{2}}{22.4\,L\,N_{2}}\times\frac{28.01\,g\,N_{2}}{1\,mol\,N_{2}}$ $=0.405\,g$ (c) $139\,cm^{3}\,Ar\times\frac{1\,L}{1000\,cm^{3}}\times\frac{1\,mol\,Ar}{22.4\,L\,Ar}\times\frac{39.948\,g\,Ar}{1\,mol\,Ar}$ $=0.248\,g$
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