Answer
The partial pressure of $CO_{2}$ is $0.00038\times 758 mm Hg =0.28804 mm Hg $
Work Step by Step
Using Dalton's Law of Partial Pressure, we can find the pressure an individual gas exerts in a mixture of gases.
$Partial Pressure = Mole Fraction of Gas\times Total Pressure$
Since we are told that there is $0.038$ % of $CO_{2}$, we can determine the mole fraction simply by converting the percent of $CO_{2}$ gas into a number by dividing by 100 to get $0.00038$
Therefore, the partial pressure of $CO_{2}$ is $0.00038\times 758 mm Hg =0.28804 mm Hg $
