Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 11 - Gases - Exercises - Problems - Page 402: 56

Answer

48 psi.

Work Step by Step

$\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$ (at constant V and n) $\implies P_{2}=\frac{P_{1}T_{2}}{T_{1}}=\frac{44\,psi\times (273+37)K}{(273+11)K}$ $=48\,psi$
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