Answer
$208.7 mL$
Work Step by Step
Using the combined gas law with the involved quantities we can see that
$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$
Since the question asks for the final volume, we must solve for $V_{2}$
Rearranging for $V_{2}$, we get:
$\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}=V_{2}.$ Therefore, $\frac{1.32 atm\times 0.218 L \times 335 K}{298 K\times 1.55 atm}=V_{2}.$
$V_{2} = 0.2087 L$
$V_{2} = 0.2087 L \times 1000 = 208.7 mL$
