Answer
a. 3.00 moles of $KOH$ will have a higher boiling point, since it has a greater quantity of particles in solution.
b. 0.40 moles of $Al(NO_3)_3$ will have a higher boiling point, since it has a greater quantity of particles in solution.
Work Step by Step
The number of particles of solute is proportional to the increase in the boiling point.
a. Since $LiOH$ is a strong electrolyte, each mole will produce 2 particles: $Li^+$ and $OH^-$. 1.50 moles $\times$ 2 = 3.00 moles
Since $KOH$ is a strong electrolyte, each mole will produce 2 particles: $K^{+}$ and $OH^-$. 3.00 moles $\times$ 2 = 6.00 moles
6.00 moles is greater than 3.00 moles. Thus, the $KOH$ solution is going to have a higher boiling point.
b. Since $Al(NO_3)_3$ is a strong electrolyte, each mole will produce 4 particles: 1 $Al^{3+}$ and 3 $N{O_3}^-$. 0.40 mole $\times$ 4 = 1.6 moles
Since $CsCl$ is a strong electrolyte, each mole will produce 2 particles: 1 $Cs^{+}$ and 1 $Cl^-$. 0.40 mole $\times$ 2 = 0.80 mole
1.6 moles is greater than 0.80 mole. Thus, the $Al(NO_3)_3$ solution is going to have a higher boiling point.
